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4m^2+29m+7=0
a = 4; b = 29; c = +7;
Δ = b2-4ac
Δ = 292-4·4·7
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{729}=27$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(29)-27}{2*4}=\frac{-56}{8} =-7 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(29)+27}{2*4}=\frac{-2}{8} =-1/4 $
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